The canonical ensemble - N, V, T fixed.
For an ensemble,
volume = AV
# of particles = AV
energy = AV
where A is the total number of particles in a system.
Energy of each system - not fixed, but
There are
degenerate quantum states, and
Ei is repeated.
1)
2)
The occ. #, a1, a2, ..., are all eqully probable
(from a priori probability postulate). Therefore, different occ.
# have the same weight for ensemble average.
can be realized
by |
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The distribution is given by (as you have seen already)
which is just a multinomial coefficient.
Many distribution satisfies Eq. 1) and 2)
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fraction of systems (members of the ensemble) in the jth energy level |
Remember that
The average mechanical property is obtained by
3)
where Mj is the jth quantum state.
Since W(a) is a multinomial coeff. and is highly localized at maximum position (almost a d function!), if aj are sufficiently large.
We can, then, make the spread of W(a) arbitrarily small by taking aj to be large.
Then, a set of aj's other than
can be set small!
Therefore, we have
in the limit that aj goes to infinity.
It means that
4)
So, we now have to find distribution a* that maximizes W(a) with constraints that:
We are going to use Lagrange's Method of
Undertermined Multiplier on W(a). The resulting equation is
where j = 1, 2, 3, ...
Since
Then,
By using Stirling's approximation,
And, we arrive at![]()
![]()
or alternatively,![]()
Since this is the maximum distribution sharply peaked at its maximum if we choose an arbitrarily large numbers, this is now equal to most probable distribution.5)
Determination of a and
b
Rewriting Eq. 5) by using a' = 1 +
a, and summing both sides over all j,
we obtain
Eq. 4) then becomes![]()
![]()
Now, we can calculate any mechanical property by using Eq. 3). Therefore,
the average energy is given by
The quantity in the denominator persists in the equations in the canonical
ensemble. This is the canonical ensemble partition function.
6)
Pressure as mechanical property, since
or
Therefore,
Evaluation of b, two ways.
1). Through Mechanical Property
Differentiate average E with respect to V w/ constant N and b.
7)
Also differentiate average p with respect to
b w/ constant N and V
8)
From Eqs. 7) and 8), you should arrive at (Derive this!)
From thermodynamics, we know that
And, if we change the differential to
using the fact that
Therefore, the term b is
Proof of k being a universal constant
Consider a system
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NA, VA, {EAj}, aj NB, VB, {EBj}, bj |
The ensemble must satisfy
Applying most probable distribution of the AB ensemble with
systems A in ith quantum state and systems
B in jth quantum state leads to
Thus, the arbitrary systems in thermal contact have the same
b. Further, since
b = 1/kT, the constant k is a
universal constant.
2). Another way of determining b
Consider a fxn,
Then,
The total derivative of f is then,
which can be written in the form,
9)
Now, make physical change on the ensemble of systems such that
V + dVT T + dT |
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![]() ![]() Average reversible work =
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10)
It means that bdqrev is
the derivative of a state function, and b
is an integrating factor.
The left-hand side of Eq. 10) is then dS/k, and by integrating the equation to obtain
What does all these mean?
Thermodynamic Quantities from Canonical Ensemble
We have seen again, increasing the number of available system gives arise to spontaneous process in closed system.